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Question 37 of 46

Q.Calculate the current flowing through two long parallel wires carrying equal currents and separated by a distance of 1.35 cm experiencing a force per unit length of 4.76×10−24.76 \times 10^{-2} N/m.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2023Subjective· 3mImportance★★★★★
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Force per unit length between two parallel current-carrying wires gives the common current.

For two long parallel wires carrying equal currents II, separated by dd, the force per unit length is

FL=μ0I22πd\frac{F}{L} = \frac{\mu_0 I^2}{2\pi d}

Solving for I2I^2 with F/L=4.76×10−2F/L = 4.76\times10^{-2} N/m, d=1.35×10−2d=1.35\times10^{-2} m, μ0=4π×10−7\mu_0=4\pi\times10^{-7} T·m/A: …

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