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Question 43 of 46

Q.A solenoid of length π m and 5 cm in diameter has a winding of 1000 turns and carries a current of 5A. Calculate the magnetic field at its centre along the axis.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 3mImportance★★★★★
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The axial field of a long solenoid depends only on the number of turns per unit length and the current, not the diameter.

For a long solenoid, the magnetic field at a point well inside it, on the axis, is

B=μ0nIB = \mu_0 n I

where n=N/Ln = N/L is the number of turns per unit length. Given N=1000N = 1000, L=π mL = \pi\text{ m}, I=5 AI = 5\text{ A} (the 5 cm diameter is not needed for the axial field formula):

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