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Question 31 of 48

Q.At which position of the plane of the rotating coil with the direction of magnetic field, the e.m.f. induced in the coil is maximum?

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2019Subjective· 1mImportance★★★★★
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Induced emf in a rotating coil is ε=NABωsin⁡(ωt)\varepsilon=NAB\omega\sin(\omega t), which is maximum when the coil's plane is parallel to the field (i.e. the rate of change of flux is greatest).

For a coil of NN turns, area AA, rotating with angular velocity ω\omega in a uniform magnetic field BB, the flux through it is ϕ=NABcos⁡ωt\phi = NAB\cos\omega t (taking t=0t=0 when the plane is perpendicular to BB, i.e. normal parallel to BB), and the induced emf is

ε=−dϕdt=NABωsin⁡ωt\varepsilon = -\frac{d\phi}{dt} = NAB\omega\sin\omega t

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