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3.1 · Q2

Q.Evaluate: ∫x2(1−2x)2dx\int x^2\left(1-\dfrac{2}{x}\right)^2 dx

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✓ Free question

Expand (1−2x)2=1−4x+4x2\left(1-\dfrac{2}{x}\right)^2 = 1-\dfrac{4}{x}+\dfrac{4}{x^2}.

Multiplying by x2x^2: x2−4x+4x^2-4x+4.

Now integrate term by term: ∫x2 dx=x33\int x^2\,dx=\dfrac{x^3}{3}, ∫−4x dx=−2x2\int -4x\,dx=-2x^2, ∫4 dx=4x\int 4\,dx=4x.

✓Final answer

x33−2x2+4x+c\dfrac{x^3}{3}-2x^2+4x+c

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