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3.1 · Q3

Q.Evaluate: ∫(3sec⁡2x−4x+1xx−7)dx\int \left(3\sec^2 x - \dfrac{4}{x} + \dfrac{1}{x\sqrt{x}} - 7\right) dx

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✓ Free question

Split into four integrals.

∫3sec⁡2x dx=3tan⁡x\int 3\sec^2x\,dx=3\tan x.

∫−4x dx=−4ln⁡∣x∣\int -\dfrac{4}{x}\,dx=-4\ln|x|.

1xx=x−3/2\dfrac{1}{x\sqrt{x}}=x^{-3/2}, so ∫x−3/2dx=x−1/2−1/2=−2x\int x^{-3/2}dx=\dfrac{x^{-1/2}}{-1/2}=-\dfrac{2}{\sqrt{x}}.

∫−7 dx=−7x\int -7\,dx=-7x.

Sum all four pieces.

✓Final answer

3tan⁡x−4ln⁡∣x∣−2x−7x+c3\tan x-4\ln|x|-\dfrac{2}{\sqrt{x}}-7x+c

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