Skip to content
3.2(B) · Q71

Q.Evaluate: ∫17+2x2 dx\int \frac{1}{7+2x^2}\,dx

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
47% · 120/255 Questions
✓ Free question

Write 7+2x2=2(x2+72)7+2x^2=2\left(x^2+\dfrac72\right), so ∫dx7+2x2=12∫dxx2+(7/2)2\int\dfrac{dx}{7+2x^2}=\dfrac12\int\dfrac{dx}{x^2+\left(\sqrt{7/2}\right)^2}.

Using ∫dxx2+a2=1atan⁡−1xa+c\int\dfrac{dx}{x^2+a^2}=\dfrac1a\tan^{-1}\dfrac xa+c with a=7/2=142a=\sqrt{7/2}=\dfrac{\sqrt{14}}2:

integral =12⋅214tan⁡−1(2x14)+c=\dfrac12\cdot\dfrac{2}{\sqrt{14}}\tan^{-1}\left(\dfrac{2x}{\sqrt{14}}\right)+c.

✓Final answer

114tan⁡−1(2x14)+c\dfrac{1}{\sqrt{14}}\tan^{-1}\left(\dfrac{2x}{\sqrt{14}}\right)+c

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.