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3.2(B) · Q73

Q.Evaluate: ∫111−4x2 dx\int \frac{1}{\sqrt{11-4x^2}}\,dx

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Write 11−4x2=4(114−x2)11-4x^2=4\left(\dfrac{11}4-x^2\right), so ∫dx11−4x2=12∫dx(11/2)2−x2\int\dfrac{dx}{\sqrt{11-4x^2}}=\dfrac12\int\dfrac{dx}{\sqrt{\left(\sqrt{11}/2\right)^2-x^2}}.

Using ∫dxa2−x2=sin⁡−1xa+c\int\dfrac{dx}{\sqrt{a^2-x^2}}=\sin^{-1}\dfrac xa+c with a=112a=\dfrac{\sqrt{11}}2: …

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