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3.2(B) · Q83

Q.Evaluate: ∫1x2+8x−20 dx\int \frac{1}{\sqrt{x^2+8x-20}}\,dx

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Complete the square: x2+8x−20=(x+4)2−16−20=(x+4)2−36x^2+8x-20=(x+4)^2-16-20=(x+4)^2-36. …

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