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3.2(C) · Q105

Q.Evaluate: ∫3cos⁡x4sin⁡2x+4sin⁡x−1 dx\int \frac{3\cos x}{4\sin^2 x+4\sin x-1}\,dx

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Substitute t=sin⁡x, dt=cos⁡x dxt=\sin x,\ dt=\cos x\,dx: integral =3∫dt4t2+4t−1=34∫dtt2+t−14=\displaystyle3\int\dfrac{dt}{4t^2+4t-1}=\dfrac34\int\dfrac{dt}{t^2+t-\frac14}.

Complete the square: t2+t−14=(t+12)2−12t^2+t-\dfrac14=\left(t+\dfrac12\right)^2-\dfrac12.

Apply ∫duu2−a2=12alog⁡∣u−au+a∣+c\int\dfrac{du}{u^2-a^2}=\dfrac1{2a}\log\left|\dfrac{u-a}{u+a}\right|+c with u=t+12, a=12u=t+\dfrac12,\ a=\dfrac1{\sqrt2}: …

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