Skip to content
Miscellaneous 3 · Q192

Q.Integrate: ∫(x−2)2x dx\int (x-2)^2\sqrt{x}\,dx

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
8% · 21/255 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Expand (x−2)2=x2−4x+4(x-2)^2=x^2-4x+4, so the integrand is (x2−4x+4)x1/2=x5/2−4x3/2+4x1/2(x^2-4x+4)x^{1/2}=x^{5/2}-4x^{3/2}+4x^{1/2}. Integrate each term using the power rule: ∫x5/2dx=27x7/2\int x^{5/2}dx=\frac27x^{7/2}; ∫−4x3/2dx=−4⋅25x5/2=−85x5/2\int -4x^{3/2}dx=-4\cdot\frac25x^{5/2}=-\frac85x^{5/2}; $\int 4x^{1/2}dx=4\cdot\frac23x^{3/2}=\frac83x^{3/ …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.