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3.2(A) · Q62

Q.Integrate: ∫tan⁡5x dx\int \tan^5 x\,dx

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Write tan⁡5x=tan⁡3x(sec⁡2x−1)=tan⁡3xsec⁡2x−tan⁡3x\tan^5x=\tan^3x(\sec^2x-1)=\tan^3x\sec^2x-\tan^3x.

∫tan⁡3xsec⁡2x dx\int\tan^3x\sec^2x\,dx: let t=tan⁡xt=\tan x, ∫t3dt=t44=tan⁡4x4\int t^3dt=\dfrac{t^4}{4}=\dfrac{\tan^4x}{4}.

For ∫tan⁡3x dx=∫tan⁡x(sec⁡2x−1)dx=∫tan⁡xsec⁡2x dx−∫tan⁡x dx=tan⁡2x2+ln⁡∣cos⁡x∣\int\tan^3x\,dx=\int\tan x(\sec^2x-1)dx=\int\tan x\sec^2x\,dx-\int\tan x\,dx=\dfrac{\tan^2x}{2}+\ln|\cos x|. …

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