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3.2(B) · Q79

Q.Evaluate: ∫11+x−x2 dx\int \frac{1}{1+x-x^2}\,dx

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Write 1+x−x2=−(x2−x−1)=−[(x−12)2−54]=54−(x−12)21+x-x^2=-\left(x^2-x-1\right)=-\left[\left(x-\dfrac12\right)^2-\dfrac54\right]=\dfrac54-\left(x-\dfrac12\right)^2.

So ∫dx(52)2−(x−12)2\displaystyle\int\dfrac{dx}{\left(\frac{\sqrt5}2\right)^2-\left(x-\frac12\right)^2}, standard form ∫dua2−u2=12alog⁡∣a+ua−u∣+c\int\dfrac{du}{a^2-u^2}=\dfrac1{2a}\log\left|\dfrac{a+u}{a-u}\right|+c with u=x−12, a=52u=x-\frac12,\ a=\frac{\sqrt5}2: …

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