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5.1 · Q18

Q.Find the area of the triangle with vertices (1,1,0)(1,1,0), (1,0,1)(1,0,1) and (0,1,1)(0,1,1).

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Let A=(1,1,0),B=(1,0,1),C=(0,1,1)A=(1,1,0),B=(1,0,1),C=(0,1,1). Form two side vectors from AA:

AB→=B−A=(0,−1,1),AC→=C−A=(−1,0,1).\overrightarrow{AB}=B-A=(0,-1,1),\qquad \overrightarrow{AC}=C-A=(-1,0,1).

Their cross product is

AB→×AC→=∣i^j^k^0−11−101∣=i^(−1⋅1−1⋅0)−j^(0⋅1−1⋅(−1))+k^(0⋅0−(−1)(−1))=−i^−j^−k^.\overrightarrow{AB}\times\overrightarrow{AC}=\begin{vmatrix}\hat i&\hat j&\hat k\\ 0&-1&1\\ -1&0&1\end{vmatrix} =\hat i(-1\cdot1-1\cdot0)-\hat j(0\cdot1-1\cdot(-1))+\hat k(0\cdot0-(-1)(-1))=-\hat i-\hat j-\hat k. …

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