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5.1 · Q19

Q.If AB‾=2i^−4j^+7k^\overline{AB}=2\hat i-4\hat j+7\hat k and initial point A≡(1,5,0)A\equiv(1,5,0). Find the terminal point B.

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Since AB→=B−A\overrightarrow{AB}=B-A (as position vectors), B=A+AB→B=A+\overrightarrow{AB}. With A=(1,5,0)A=(1,5,0) and …

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