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5.1 · Q5

Q.OABCDE is a regular hexagon. The points A and B have position vectors aˉ\bar a and bˉ\bar b respectively, referred to the origin O. Find, in terms of aˉ\bar a and bˉ\bar b, the position vectors of C, D and E.

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Set up coordinates with the hexagon's centre at the origin, vertices at 60∘60^\circ steps, then shift so that

vertex OO becomes the new origin. Writing the position vectors of AA and BB (relative to OO) as aˉ\bar a

and bˉ\bar b, and solving for the coordinates of C,D,EC,D,E in terms of aˉ,bˉ\bar a,\bar b using this rotational

structure (each vertex is obtained from the previous by rotating the edge direction by the hexagon's exterior

angle of 60∘60^\circ) gives:

OC→=2bˉ−2aˉ=2(bˉ−aˉ),OD→=2bˉ−3aˉ,OE→=bˉ−2aˉ.\overrightarrow{OC}=2\bar b-2\bar a=2(\bar b-\bar a),\qquad \overrightarrow{OD}=2\bar b-3\bar a,\qquad \overrightarrow{OE}=\bar b-2\bar a.

These can be checked for self-consistency: since OO and CC are opposite vertices of the hexagon 3 steps

apart, and likewise A,DA,D and B,EB,E are opposite pairs, the three "long diagonals" OC,AD,BEOC, AD, BE must all share …

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