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MiscII · Q138

Q.Express the vector aˉ=5i^−2j^+5k^\bar a=5\hat i-2\hat j+5\hat k as a sum of two vectors such that one is parallel to the vector bˉ=3i^+k^\bar b=3\hat i+\hat k and other is perpendicular to bˉ\bar b.

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aˉ=5i^−2j^+5k^, bˉ=3i^+k^\bar a=5\hat i-2\hat j+5\hat k,\ \bar b=3\hat i+\hat k. The component of aˉ\bar a parallel to bˉ\bar b is

the vector projection:

aˉ∥=aˉ⋅bˉ∣bˉ∣2bˉ.\bar a_\parallel=\frac{\bar a\cdot\bar b}{|\bar b|^2}\bar b.

aˉ⋅bˉ=5(3)+(−2)(0)+5(1)=15+5=20\bar a\cdot\bar b=5(3)+(-2)(0)+5(1)=15+5=20. ∣bˉ∣2=9+0+1=10|\bar b|^2=9+0+1=10.

aˉ∥=2010bˉ=2(3i^+k^)=6i^+2k^.\bar a_\parallel=\frac{20}{10}\bar b=2(3\hat i+\hat k)=6\hat i+2\hat k.

The perpendicular component is the remainder:

aˉ⊥=aˉ−aˉ∥=(5i^−2j^+5k^)−(6i^+0j^+2k^)=−i^−2j^+3k^.\bar a_\perp=\bar a-\bar a_\parallel=(5\hat i-2\hat j+5\hat k)-(6\hat i+0\hat j+2\hat k)=-\hat i-2\hat j+3\hat k. …

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