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MiscII · Q125

Q.Find the unit vectors that are parallel to the tangent line to the parabola y=x2y=x^2 at the point (2,4)(2,4).

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For y=x2y=x^2, dydx=2x\dfrac{dy}{dx}=2x; at x=2x=2 (the point (2,4)(2,4)), the slope is 44. A direction vector along

the tangent line (slope 4 means "run 1, rise 4") is i^+4j^\hat i+4\hat j, with magnitude 1+16=17\sqrt{1+16}=\sqrt{17}. …

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