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7.2 Q.I · Q24

Q.lim⁡x→−2[−2x−4x3+2x2]\displaystyle\lim_{x\to -2}\left[\frac{-2x-4}{x^3+2x^2}\right]

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−2x−4=−2(x+2)-2x-4=-2(x+2) and x3+2x2=x2(x+2)x^3+2x^2=x^2(x+2). Cancelling (x+2)(x+2): −2x2\dfrac{-2}{x^2}. At x=−2x=-2: $\dfrac{-2} …

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