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7.3 Q.III · Q49

Q.lim⁡z→4[3−5+z1−5−z]\displaystyle\lim_{z\to 4}\left[\frac{3-\sqrt{5+z}}{1-\sqrt{5-z}}\right]

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Multiply the numerator by 3+5+z3+\sqrt{5+z}: it becomes 9−(5+z)=4−z=−(z−4)9-(5+z)=4-z=-(z-4). Multiply the denominator by 1+5−z1+\sqrt{5-z}: it becomes 1−(5−z)=z−41-(5-z)=z-4. So the expression becomes $\dfrac{-(z-4)/(3+\sqrt{5+z})}{(z-4)/(1+\sqrt{5-z})}=\dfrac{-(1+\sqrt{5-z})}{3+\sqrt{5+z}} …

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