Skip to content
7.4 Q.I · Q52

Q.lim⁡θ→0[1−cos⁡2θθ2]\displaystyle\lim_{\theta\to 0}\left[\frac{1-\cos 2\theta}{\theta^2}\right]

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
66% · 91/137 Questions
✓ Free question

By the half-angle identity, 1−cos⁡2θ=2sin⁡2θ1-\cos2\theta=2\sin^2\theta. So the expression is 2sin⁡2θθ2=2(sin⁡θθ)2→2(1)2=2\dfrac{2\sin^2\theta}{\theta^2}=2\left(\dfrac{\sin\theta}{\theta}\right)^2\to2(1)^2=2.

✓Final answer

22

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.