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7.7 III · Q97

Q.lim⁡x→∞[(2x−1)20(3x−1)30(2x+1)50]\displaystyle\lim_{x\to \infty}\left[\frac{(2x-1)^{20}(3x-1)^{30}}{(2x+1)^{50}}\right]

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Leading behaviour: (2x−1)20∼(2x)20=220x20(2x-1)^{20}\sim(2x)^{20}=2^{20}x^{20}, (3x−1)30∼(3x)30=330x30(3x-1)^{30}\sim(3x)^{30}=3^{30}x^{30}, (2x+1)50∼(2x)50=250x50(2x+1)^{50}\sim(2x)^{50}=2^{50}x^{50}. The total power of xx in the numerator is 20+30=5020+30=50, exactly matching the denominator, so it's a genuine finite limit: $\dfrac{2^{20 …

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