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Miscellaneous 7 II · Q129

Q.lim⁡x→a[xcos⁡a−acos⁡xx−a]\displaystyle\lim_{x\to a}\left[\frac{x\cos a-a\cos x}{x-a}\right]

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xcos⁡a−acos⁡x=xcos⁡a−acos⁡a+acos⁡a−acos⁡x=cos⁡a(x−a)+a(cos⁡a−cos⁡x)x\cos a-a\cos x=x\cos a-a\cos a+a\cos a-a\cos x=\cos a(x-a)+a(\cos a-\cos x). Dividing by (x−a)(x-a): cos⁡a+a⋅cos⁡a−cos⁡xx−a\cos a+a\cdot\dfrac{\cos a-\cos x}{x-a}. Now cos⁡a−cos⁡xx−a=−cos⁡x−cos⁡ax−a→−(−sin⁡a)=sin⁡a\dfrac{\cos a-\cos x}{x-a}=-\dfrac{\cos x-\cos a}{x-a}\to-(-\sin a)=\sin a (using the standard result $ …

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