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7.7 I · Q89

Q.lim⁡x→∞[x3+3x+2(x+4)(x−6)(x−3)]\displaystyle\lim_{x\to \infty}\left[\frac{x^3+3x+2}{(x+4)(x-6)(x-3)}\right]

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The numerator x3+3x+2x^3+3x+2 has leading term x3x^3 (coefficient 1). Expanding (x+4)(x−6)(x−3)(x+4)(x-6)(x-3) gives leading term x3x^3 as well (coefficient 1). Dividing by x3x^3 and letting $x\to …

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