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Miscellaneous 7 II · Q127

Q.lim⁡x→0[(5x−1)2(2x−1)log⁡(1+x)]\displaystyle\lim_{x\to 0}\left[\frac{(5^x-1)^2}{(2^x-1)\log(1+x)}\right]

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(5x−1)2∼(xlog⁡5)2=x2(log⁡5)2(5^x-1)^2\sim(x\log5)^2=x^2(\log5)^2. Denominator: (2x−1)log⁡(1+x)∼(xlog⁡2)(x)=x2log⁡2(2^x-1)\log(1+x)\sim(x\log2)(x)=x^2\log2. The limit is $\dfrac{(\log …

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