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7.4 Q.I · Q53

Q.lim⁡x→0[x⋅tan⁡x1−cos⁡x]\displaystyle\lim_{x\to 0}\left[\frac{x\cdot\tan x}{1-\cos x}\right]

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Multiply numerator and denominator by (1+cos⁡x)(1+\cos x): $\dfrac{x\tan x(1+\cos x)}{(1-\cos x)(1+\cos x)}=\dfrac{x\tan x(1+\cos x)}{\sin^2x}=\dfrac{x\sin x(1+\cos x)}{\cos x\sin^2x}=\dfrac{x(1+\cos x)}{\cos x\sin x} …

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