Skip to content
Miscellaneous 7 I · Q107

Q.lim⁡x→0(3+5x3−4x)1/x=\displaystyle\lim_{x\to 0}\left(\frac{3+5x}{3-4x}\right)^{1/x}= (A) e3e^3 (B) e6e^6 (C) e9e^9 (D) e−3e^{-3}

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
7% · 9/137 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

3+5x3−4x−1=9x3−4x\dfrac{3+5x}{3-4x}-1=\dfrac{9x}{3-4x}. The exponent's limit is lim⁡x→01x⋅9x3−4x=93=3\lim_{x\to0}\dfrac1x\cdot\dfrac{9x}{3-4x}=\dfrac93=3. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.