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7.2 Q.II · Q26

Q.lim⁡u→1[u4−1u3−1]\displaystyle\lim_{u\to 1}\left[\frac{u^4-1}{u^3-1}\right]

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✓ Free question

By the standard theorem at a=1a=1, lim⁡u→1u4−1u−1=4(1)3=4\lim_{u\to1}\dfrac{u^4-1}{u-1}=4(1)^3=4 and lim⁡u→1u3−1u−1=3(1)2=3\lim_{u\to1}\dfrac{u^3-1}{u-1}=3(1)^2=3. Dividing (the common factor u−1u-1 cancels top and bottom): 43\dfrac{4}{3}.

✓Final answer

43\dfrac{4}{3}

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