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7.7 II · Q92

Q.lim⁡x→∞[x2+4x+16−x2+16]\displaystyle\lim_{x\to \infty}\left[\sqrt{x^2+4x+16}-\sqrt{x^2+16}\right]

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Multiply by the conjugate: (x2+4x+16)−(x2+16)x2+4x+16+x2+16=4xx2+4x+16+x2+16\dfrac{(x^2+4x+16)-(x^2+16)}{\sqrt{x^2+4x+16}+\sqrt{x^2+16}}=\dfrac{4x}{\sqrt{x^2+4x+16}+\sqrt{x^2+16}}. Dividing numerator and denominator by xx (positive, as x→∞x\to\infty) …

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