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Miscellaneous 7 I · Q112

Q.lim⁡x→3[5x−3−4x−3sin⁡(x−3)]=\displaystyle\lim_{x\to 3}\left[\frac{5^{x-3}-4^{x-3}}{\sin(x-3)}\right]= (A) log⁡5−4\log 5-4 (B) log⁡54\log \dfrac{5}{4} (C) log⁡5log⁡4\dfrac{\log 5}{\log 4} (D) log⁡54\dfrac{\log 5}{4}

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Let u=x−3→0u=x-3\to0. 5x−3−4x−3=5u−4u∼u(log⁡5−log⁡4)=ulog⁡(5/4)5^{x-3}-4^{x-3}=5^u-4^u\sim u(\log5-\log4)=u\log(5/4). Denominator sin⁡(x−3)=sin⁡u∼u\sin(x-3)=\sin u\sim u. The limit …

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