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7.7 II · Q91

Q.lim⁡x→∞[7x2+2x−3x4+x+2]\displaystyle\lim_{x\to \infty}\left[\frac{7x^2+2x-3}{\sqrt{x^4+x+2}}\right]

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Divide the numerator by x2x^2: →7\to7. For the denominator, x4+x+2=x21+1/x3+2/x4→x2×1\sqrt{x^4+x+2}=x^2\sqrt{1+1/x^3+2/x^4}\to x^2\times1 for large positive xx; dividing the whole denominator by x2x^2 gives 1+1/x3+2/x4→1\sqrt{1+1/x^3+2/x^4}\to1. So the ratio is 71=7\dfrac71=7.

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