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7.3 Q.II · Q44

Q.lim⁡y→0[a+y−aya+y]\displaystyle\lim_{y\to 0}\left[\frac{\sqrt{a+y}-\sqrt{a}}{y\sqrt{a+y}}\right]

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Multiply by the conjugate a+y+a\sqrt{a+y}+\sqrt a: the numerator becomes (a+y)−a=y(a+y)-a=y. So the expression is yya+y(a+y+a)=1a+y(a+y+a)\dfrac{y}{y\sqrt{a+y}(\sqrt{a+y}+\sqrt a)}=\dfrac{1}{\sqrt{a+y}(\sqrt{a+y}+\sqrt a)} after cancelling yy. At y=0y=0: $\dfrac{1}{\ …

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