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7.6 Q.II · Q80

Q.lim⁡x→0[log⁡(3−x)−log⁡(3+x)]/x\displaystyle\lim_{x\to 0}\left[\log(3-x)-\log(3+x)\right]/x

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log⁡(3−x)−log⁡(3+x)=log⁡ ⁣(1−x3)−log⁡ ⁣(1+x3)\log(3-x)-\log(3+x)=\log\!\left(1-\dfrac x3\right)-\log\!\left(1+\dfrac x3\right) (factoring out log⁡3\log3 from each, which cancels). Dividing by xx: $\dfrac{\log(1-x/3)}{x}-\dfrac{\log(1+x/3)}{x}\to\left(-\dfrac13\right)-\left(\dfrac13\right)=-\dfra …

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