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Miscellaneous 7 II · Q120

Q.lim⁡x→0[sec⁡(x2)−1x4]\displaystyle\lim_{x\to 0}\left[\frac{\sec(x^2)-1}{x^4}\right]

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sec⁡(x2)−1=1−cos⁡(x2)cos⁡(x2)=2sin⁡2(x2/2)cos⁡(x2)\sec(x^2)-1=\dfrac{1-\cos(x^2)}{\cos(x^2)}=\dfrac{2\sin^2(x^2/2)}{\cos(x^2)}. Dividing by x4=4(x2/2)2x^4=4(x^2/2)^2: $\dfrac{2\sin^2(x^2/2)}{4(x^2/2)^2\cos(x^2)}=\dfrac12\left(\dfrac{\sin(x^2/2)}{x^2/2}\righ …

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