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7.6 Q.III · Q84

Q.lim⁡x→0[(2x−1)3(3x−1)⋅sin⁡x⋅log⁡(1+x)]\displaystyle\lim_{x\to 0}\left[\frac{(2^x-1)^3}{(3^x-1)\cdot\sin x\cdot \log(1+x)}\right]

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✓ Free question

(2x−1)3∼(xlog⁡2)3=x3(log⁡2)3(2^x-1)^3\sim(x\log2)^3=x^3(\log2)^3. Denominator: (3x−1)sin⁡xlog⁡(1+x)∼(xlog⁡3)(x)(x)=x3log⁡3(3^x-1)\sin x\log(1+x)\sim(x\log3)(x)(x)=x^3\log3. So the limit is x3(log⁡2)3x3log⁡3=(log⁡2)3log⁡3\dfrac{x^3(\log2)^3}{x^3\log3}=\dfrac{(\log2)^3}{\log3}.

✓Final answer

(log⁡2)3log⁡3\dfrac{(\log2)^3}{\log3}

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