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Miscellaneous 7 I · Q111

Q.lim⁡x→0[(3sin⁡x−1)3(3x−1)⋅tan⁡x⋅log⁡(1+x)]=\displaystyle\lim_{x\to 0}\left[\frac{(3^{\sin x}-1)^3}{(3^x-1)\cdot\tan x\cdot\log(1+x)}\right]= (A) 3log⁡33\log 3 (B) 2log⁡32\log 3 (C) (log⁡3)2(\log 3)^2 (D) (log⁡3)3(\log 3)^3

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3sin⁡x−1∼(sin⁡x)log⁡3∼xlog⁡33^{\sin x}-1\sim(\sin x)\log3\sim x\log3, so the numerator (3sin⁡x−1)3∼x3(log⁡3)3(3^{\sin x}-1)^3\sim x^3(\log3)^3. Denominator: (3x−1)tan⁡xlog⁡(1+x)∼(xlog⁡3)(x)(x)=x3log⁡3(3^x-1)\tan x\log(1+x)\sim(x\log3)(x)(x)=x^3\log3. The limit is $\ …

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