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7.7 I · Q88

Q.lim⁡x→∞[ax3+bx2+cx+dex3+fx2+gx+h]\displaystyle\lim_{x\to \infty}\left[\frac{ax^3+bx^2+cx+d}{ex^3+fx^2+gx+h}\right]

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Dividing numerator and denominator by x3x^3: a+b/x+c/x2+d/x3e+f/x+g/x2+h/x3\dfrac{a+b/x+c/x^2+d/x^3}{e+f/x+g/x^2+h/x^3}. As x→∞x\to\infty, every term with xx in the denominator vanishes, leaving ae\dfrac ae.

✓Final answer

ae\dfrac{a}{e}

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