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7.7 III · Q96

Q.lim⁡x→∞[x(x+1−x)]\displaystyle\lim_{x\to \infty}\left[\sqrt{x}\left(\sqrt{x+1}-\sqrt{x}\right)\right]

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x(x+1−x)=x⋅(x+1)−xx+1+x=xx+1+x\sqrt x\left(\sqrt{x+1}-\sqrt x\right)=\sqrt x\cdot\dfrac{(x+1)-x}{\sqrt{x+1}+\sqrt x}=\dfrac{\sqrt x}{\sqrt{x+1}+\sqrt x}. Dividing numerator and denominator by x\sqrt x: $\df …

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