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7.5 II · Q70

Q.lim⁡x→a[sin⁡(x)−sin⁡(a)x−a]\displaystyle\lim_{x\to a}\left[\frac{\sin\left(\sqrt{x}\right)-\sin\left(\sqrt{a}\right)}{x-a}\right]

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sin⁡x−sin⁡a=2cos⁡ ⁣(x+a2)sin⁡ ⁣(x−a2)\sin\sqrt x-\sin\sqrt a=2\cos\!\left(\dfrac{\sqrt x+\sqrt a}2\right)\sin\!\left(\dfrac{\sqrt x-\sqrt a}2\right). As x→ax\to a, x−a→0\sqrt x-\sqrt a\to0, so sin⁡ ⁣(x−a2)∼x−a2\sin\!\left(\tfrac{\sqrt x-\sqrt a}2\right)\sim\tfrac{\sqrt x-\sqrt a}2. Also x−a=(x−a)(x+a)x-a=(\sqrt x-\sqrt a)(\sqrt x+\sqrt a). So the expression $\sim\dfrac{2\cos!\left(\tfrac{\sqrt x+\sqrt a}2\right)\cdot\tfrac{\sqrt x-\sqrt a}2}{(\sqrt x-\sqrt a)(\sq …

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