7.3 Q.I · Q40
Q.
Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
58% · 79/137 Questions
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Start your 14-day free trial to unlock the full solution →Multiply top and bottom by and by respectively: numerator becomes ; denominator (of the conjugate-multiplied bottom) becomes . So the expression rearranges to $\dfrac{2(x-2)}{\sqrt{2+x}+\sqrt{6-x}}\times\dfrac{\sqrt x+\sqrt2}{x-2}=\dfrac{2(\sqrt x+\sqrt2)}{\sqrt{2+x}+ …
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