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7.3 Q.I · Q40

Q.lim⁡x→2[2+x−6−xx−2]\displaystyle\lim_{x\to 2}\left[\frac{\sqrt{2+x}-\sqrt{6-x}}{\sqrt{x}-\sqrt2}\right]

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Multiply top and bottom by 2+x+6−x\sqrt{2+x}+\sqrt{6-x} and by x+2\sqrt x+\sqrt2 respectively: numerator becomes (2+x)−(6−x)=2x−4=2(x−2)(2+x)-(6-x)=2x-4=2(x-2); denominator (of the conjugate-multiplied bottom) becomes x−2x-2. So the expression rearranges to $\dfrac{2(x-2)}{\sqrt{2+x}+\sqrt{6-x}}\times\dfrac{\sqrt x+\sqrt2}{x-2}=\dfrac{2(\sqrt x+\sqrt2)}{\sqrt{2+x}+ …

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