Skip to content
7.4 Q.I · Q51

Q.lim⁡θ→0[sin⁡(mθ)tan⁡(nθ)]\displaystyle\lim_{\theta\to 0}\left[\frac{\sin(m\theta)}{\tan(n\theta)}\right]

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
66% · 90/137 Questions
✓ Free question

Write sin⁡(mθ)tan⁡(nθ)=sin⁡(mθ)mθ×nθtan⁡(nθ)×mn\dfrac{\sin(m\theta)}{\tan(n\theta)}=\dfrac{\sin(m\theta)}{m\theta}\times\dfrac{n\theta}{\tan(n\theta)}\times\dfrac{m}{n}. As θ→0\theta\to0, both mθ→0m\theta\to0 and nθ→0n\theta\to0, so the first ratio →1\to1 and the second ratio →1\to1 by the standard corollaries. The limit is 1×1×mn=mn1\times1\times\dfrac mn=\dfrac mn.

✓Final answer

mn\dfrac{m}{n}

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.