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7.7 I · Q90

Q.lim⁡x→∞[7x2+5x−38x2−2x+7]\displaystyle\lim_{x\to \infty}\left[\frac{7x^2+5x-3}{8x^2-2x+7}\right]

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Dividing numerator and denominator by x2x^2: 7+5/x−3/x28−2/x+7/x2→78\dfrac{7+5/x-3/x^2}{8-2/x+7/x^2}\to\dfrac78 as …

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