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EXERCISE 1.2 · Q65

Q.Differentiate the following w.r.t. xx: sin⁡−1(x3/2)\sin^{-1}(x^{3/2})

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Let u=x3/2u=x^{3/2}, so u′=32x1/2u'=\dfrac32x^{1/2}. Using ddxsin⁡−1u=u′1−u2\dfrac{d}{dx}\sin^{-1}u=\dfrac{u'}{\sqrt{1-u^2}}, and u2=x3u^2=x^3, we get $\dfrac{dy}{dx}=\dfrac{\frac32\sqrt x}{\sqrt{1-x^3}}=\d …

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