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EXERCISE 1.5 · Q207

Q.cos⁡x\cos x

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Let y=cos⁡xy=\cos x.

Step 1: y1=−sin⁡xy_1=-\sin x. Using −sin⁡x=cos⁡(x+π/2)-\sin x=\cos(x+\pi/2), this is y1=cos⁡(x+π/2)y_1=\cos(x+\pi/2).

Step 2: y2=−cos⁡x=cos⁡(x+π)y_2=-\cos x=\cos(x+\pi).

Step 3: y3=sin⁡x=cos⁡(x+3π/2)y_3=\sin x=\cos(x+3\pi/2).

Step 4: y4=cos⁡x=cos⁡(x+2π)y_4=\cos x=\cos(x+2\pi), back to the start — confirming a π/2\pi/2 shift per differentiation. …

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