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EXERCISE 1.5 · Q180

Q.2x5−4x3−2x2−92x^5-4x^3-\dfrac{2}{x^2}-9

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✓ Free question

Let y=2x5−4x3−2x−2−9y=2x^5-4x^3-2x^{-2}-9 (rewriting 2x2\dfrac{2}{x^2} as 2x−22x^{-2} so every term is a clean power of xx).

Step 1 — differentiate once, term by term: dydx=10x4−12x2−2(−2)x−3=10x4−12x2+4x−3\dfrac{dy}{dx}=10x^4-12x^2-2(-2)x^{-3}=10x^4-12x^2+4x^{-3}.

Step 2 — differentiate again, term by term: d2ydx2=40x3−24x+4(−3)x−4=40x3−24x−12x−4\dfrac{d^2y}{dx^2}=40x^3-24x+4(-3)x^{-4}=40x^3-24x-12x^{-4}.

Rewriting x−4x^{-4} back as 1/x41/x^4:

d2ydx2=40x3−24x−12x4\dfrac{d^2y}{dx^2}=40x^3-24x-\dfrac{12}{x^4}

✓Final answer

d2ydx2=40x3−24x−12x4\dfrac{d^2y}{dx^2}=40x^3-24x-\dfrac{12}{x^4}

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