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MISCELLANEOUS EXERCISE 1 (II) · Q245

Q.Differentiate log⁡1+x2+x1+x2−x\log\dfrac{\sqrt{1+x^2}+x}{\sqrt{1+x^2}-x} w.r.t. cos⁡(log⁡x)\cos(\log x)

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Reduce uu: rationalize the fraction inside the log by multiplying numerator and denominator by (1+x2+x)(\sqrt{1+x^2}+x):

1+x2+x1+x2−x=(1+x2+x)2(1+x2)−x2=(1+x2+x)2.\frac{\sqrt{1+x^2}+x}{\sqrt{1+x^2}-x}=\frac{(\sqrt{1+x^2}+x)^2}{(1+x^2)-x^2}=(\sqrt{1+x^2}+x)^2.

So u=log⁡(1+x2+x)2=2log⁡(1+x2+x)u=\log(\sqrt{1+x^2}+x)^2=2\log(\sqrt{1+x^2}+x).

dudx=2⋅x1+x2+11+x2+x=2⋅x+1+x21+x21+x2+x=21+x2.\frac{du}{dx}=2\cdot\frac{\dfrac{x}{\sqrt{1+x^2}}+1}{\sqrt{1+x^2}+x}=2\cdot\frac{\dfrac{x+\sqrt{1+x^2}}{\sqrt{1+x^2}}}{\sqrt{1+x^2}+x}=\frac{2}{\sqrt{1+x^2}}. …

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