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EXERCISE 1.4 · Q163

Q.Find dydx\dfrac{dy}{dx} if x=t+2sin⁡(πt)x=t+2\sin(\pi t), y=3t−cos⁡(πt)y=3t-\cos(\pi t), at t=12t=\dfrac12.

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We have x=t+2sin⁡(πt)x=t+2\sin(\pi t), y=3t−cos⁡(πt)y=3t-\cos(\pi t).

Step 1. dxdt=1+2πcos⁡(πt)\dfrac{dx}{dt}=1+2\pi\cos(\pi t)

Step 2. dydt=3+πsin⁡(πt)\dfrac{dy}{dt}=3+\pi\sin(\pi t)

Step 3. At t=12t=\dfrac12: cos⁡π2=0\cos\dfrac{\pi}{2}=0, sin⁡π2=1\sin\dfrac{\pi}{2}=1.

dxdt=1+2π(0)=1\frac{dx}{dt}=1+2\pi(0)=1 …

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