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MISCELLANEOUS EXERCISE 1 (I) · Q225

Q.If y=acos⁡(log⁡x)y=a\cos(\log x) and Ad2ydx2+Bdydx+Cy=0A\dfrac{d^2y}{dx^2}+B\dfrac{dy}{dx}+Cy=0, then the values of A, B, C are: (A) x2,−x,−1x^2,-x,-1 (B) x2,x,1x^2,x,1 (C) x2,x,−1x^2,x,-1 (D) x2,−x,1x^2,-x,1

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y=acos⁡(log⁡x)y=a\cos(\log x).

y′=−asin⁡(log⁡x)⋅1x=−asin⁡(log⁡x)x.y'=-a\sin(\log x)\cdot\frac1x=-\frac{a\sin(\log x)}{x}.

Differentiate again (quotient/product rule):

y′′=−acos⁡(log⁡x)⋅1x⋅x−(−asin⁡(log⁡x))⋅1x2=−acos⁡(log⁡x)+asin⁡(log⁡x)x2.y''=\frac{-a\cos(\log x)\cdot\frac1x\cdot x-\big(-a\sin(\log x)\big)\cdot1}{x^2}=\frac{-a\cos(\log x)+a\sin(\log x)}{x^2}.

Multiply by x2x^2: x2y′′=asin⁡(log⁡x)−acos⁡(log⁡x)=asin⁡(log⁡x)−yx^2y''=a\sin(\log x)-a\cos(\log x)=a\sin(\log x)-y. …

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