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EXERCISE 1.4 · Q160

Q.Find dydx\dfrac{dy}{dx} if x=acos⁡3θx=a\cos^3\theta, y=asin⁡3θy=a\sin^3\theta, at θ=π3\theta=\dfrac{\pi}{3}.

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We have x=acos⁡3θx=a\cos^3\theta, y=asin⁡3θy=a\sin^3\theta.

Step 1. dxdθ=−3acos⁡2θsin⁡θ\dfrac{dx}{d\theta}=-3a\cos^2\theta\sin\theta

Step 2. dydθ=3asin⁡2θcos⁡θ\dfrac{dy}{d\theta}=3a\sin^2\theta\cos\theta

Step 3.

dydx=3asin⁡2θcos⁡θ−3acos⁡2θsin⁡θ=−sin⁡θcos⁡θ=−tan⁡θ\frac{dy}{dx}=\frac{3a\sin^2\theta\cos\theta}{-3a\cos^2\theta\sin\theta}=-\frac{\sin\theta}{\cos\theta}=-\tan\theta …

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