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EXERCISE 1.5 · Q184

Q.log⁡(log⁡x)\log(\log x)

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Let y=log⁡(log⁡x)y=\log(\log x).

Step 1 — first derivative by the chain rule: dydx=1log⁡x⋅1x=1xlog⁡x\dfrac{dy}{dx}=\dfrac{1}{\log x}\cdot\dfrac1x=\dfrac{1}{x\log x}.

Step 2 — write y1=(xlog⁡x)−1y_1=(x\log x)^{-1} and differentiate using the power/chain rule: d2ydx2=−(xlog⁡x)−2⋅ddx(xlog⁡x)\dfrac{d^2y}{dx^2}=-(x\log x)^{-2}\cdot\dfrac{d}{dx}(x\log x). …

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