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EXERCISE 1.5 · Q206

Q.log⁡(ax+b)\log(ax+b)

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Let y=log⁡(ax+b)y=\log(ax+b).

Step 1: y1=aax+b=a(ax+b)−1y_1=\dfrac{a}{ax+b}=a(ax+b)^{-1}.

Step 2: y2=a⋅(−1)a(ax+b)−2=−a2(ax+b)−2y_2=a\cdot(-1)a(ax+b)^{-2}=-a^2(ax+b)^{-2}.

Step 3: y3=−a2⋅(−2)a(ax+b)−3=2a3(ax+b)−3y_3=-a^2\cdot(-2)a(ax+b)^{-3}=2a^3(ax+b)^{-3}.

Step 4: y4=2a3⋅(−3)a(ax+b)−4=−6a4(ax+b)−4y_4=2a^3\cdot(-3)a(ax+b)^{-4}=-6a^4(ax+b)^{-4}. …

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